Bernoulli’s Equation MCQ Quiz - Objective Question with Answer for Bernoulli’s Equation - Download Free PDF

Latest Bernoulli’s Equation MCQ Objective Questions

Bernoulli’s Equation Question 1:

Given below are two statements :

Statement I : When speed of liquid is zero everywhere, pressure difference at any two points depends on equation P1 – P2 = ρg (h2 – h1)

Statement II : In ventury tube shown \(2gh = \nu_1^2 - \nu_2^2\)

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In the light of the above statements, choose the most appropriate answer from the options given below.

  1. Both Statement I and Statement II are correct
  2. Statement I is incorrect but Statement II is correct
  3. Both Statement I and Statement II are incorrect
  4. Statement I is correct but Statement II is incorrect

Answer (Detailed Solution Below)

Option 4 : Statement I is correct but Statement II is incorrect India's Super Teachers for all govt. exams Under One Roof Demo Classes Available* Enroll For Free Now

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Bernoulli’s Equation Question 1 Detailed Solution

Concept:

Bernoulli's equation -

The equation states that the total mechanical energy along a streamline is constant.

\(P_1 + ρ gh_1 + \fracρ v_1^2 = P_2 + ρ gh_2 + \fracρ v_2^2\)

Where, P = The pressure exerted by the fluid at a given point in the flow.

\( \fracρ v^2 \) This represents the kinetic energy per unit volume of the fluid due to its motion.

Calculation:

Applying Bernoulli's equation

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\(P_1 + ρ gh_1 + \fracρ v_1^2 = P_2 + ρ gh_2 + \fracρ v_2^2\)

[h1 & h2 are are height of point from any reference level]

Given V1 = V2 = 0 (for statement-1)

\(P_1 + \frac ρ v_1^2 = P_2 + \frac ρ v_2^2\)

\(P_1 - P_2 = \frac\rho v_2^2 - \frac \rho v_1^2\)

\(\rho gh = \frac \rho v_2^2 - \frac\rho v_1^2\)

\(2gh = v_2^2 - v_1^2\)

∴ The correct option is (4)

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Bernoulli’s Equation Question 2:

The expression for Bernoulli’s equation is given by-
  1. \(P+\fracρ v^2 = constant\)
  2. \(P+\fracρ v^2 + ρ gh = constant\)
  3. \(\rho+\fracρ v^2 + ρ gh = constant\)
  4. \(P+\fracρ v^3 + ρ gh = constant\)
  5. Not Attempted

Answer (Detailed Solution Below)

Option 2 : \(P+\frac<1>ρ v^2 + ρ gh = constant\)

Bernoulli’s Equation Question 2 Detailed Solution

CONCEPT :


\(P+\fracρ v^2 + ρ gh = constant\)

EXPLANATION:

F1 J.K Madhu 15.05.20 D9

It can be expressed as Mathematically

\(P+\fracρ v^2 + ρ gh = constant\)

Where P is pressure in the fluid, ρ is the density of the fluid, h is the mean height, g is the acceleration due to gravity.

Additional Information

\(K.E per unit volume = \frac\fracv^2= \fracρ v^2\) where M/V is density, v is the velocity of the fluid , ρ is the density of the fluid.

​P.E per unit volume = mgh/V = ρgh